An object with a mass of $6 kg$ is revolving around a point at a distance of $2 m$ . If the object is making revolutions at a frequency of $15 Hz$ , what is the centripetal force acting on the object?

Question

1994 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-22T18:19:57

$108pi^2color(white)(x)"N"$

Centripetal force is given by:

$F=(mv^2)/r$

To find $v:$

$f=15"Hz"$

So the time period $T$ is given by:

$T=1/f=1/15s$

$:.v=(2pir)/(1/15)=30pir$

$:.F=(6xx(3pir)^2)/r$

$F=(6xx9pi^2r^(cancel2))/cancel(r)$

$F=54pi^(2)xx2=108pi^(2)color(white)(x)"N"$

An object with a mass of 6 kg6 kg is revolving around a point at a distance of 2 m2 m. If the object is making revolutions at a frequency of 15 Hz15 Hz, what is the centripetal force acting on the object?