An object with a mass of $6 kg$ is revolving around a point at a distance of $4 m$ . If the object is making revolutions at a frequency of $1 Hz$ , what is the centripetal force acting on the object?

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An object with a mass of $6 kg$ is revolving around a point at a distance of $4 m$ . If the object is making revolutions at a frequency of $1 Hz$ , what is the centripetal force acting on the object?

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Answer 1 · 2016-02-08T13:57:42

$F_c=48*pi$

Explanation:

$"The centripetal force is given by formula :" F_c=m*v^2/r$
$"we can write: " v=omega*r$
$F_c=m*omega^2*r^2/r$
$F_c=m*omega^2*r$
$omega=2*pi*f$
$F_c=6*2*pi*1*4$
$F_c=48*pi$

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An object with a mass of $6 kg$ is revolving around a point at a distance of $4 m$ . If the object is making revolutions at a frequency of $1 Hz$ , what is the centripetal force acting on the object?

1 Answer

Explanation:

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Science

Math

Humanities

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An object with a mass of 6 kg6 kg is revolving around a point at a distance of 4 m4 m. If the object is making revolutions at a frequency of 1 Hz1 Hz, what is the centripetal force acting on the object?

1 Answer

Explanation:

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An object with a mass of $6 kg$ is revolving around a point at a distance of $4 m$ . If the object is making revolutions at a frequency of $1 Hz$ , what is the centripetal force acting on the object?