An object with a mass of 6kg is revolving around a point at a distance of 8m. If the object is making revolutions at a frequency of 1Hz, what is the centripetal force acting on the object?

1 Answer
Feb 14, 2016

F=mω2r=6(2π)28=1895 N.

Explanation:

In a linear frame the centripetal force is described as F=mv2r and in a rotational frame as F=mω2r where ω is measured in radians.

1 Hz is 2π rads1, so F=6(2π)28=1895 N.