An object with a mass of $6 kg$ is revolving around a point at a distance of $8 m$ . If the object is making revolutions at a frequency of $3 Hz$ , what is the centripetal force acting on the object?

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Answer 1 · 2016-05-03T17:47:02

$17037.4N$

The centripetal force acting on an object of massm,revolving round a circular path of radius r with frequency n is given by

$F_c=m*4(pin)^2*r=6*4(3.14*3)^2*8=17037.4N$

An object with a mass of 6 kg6 kg is revolving around a point at a distance of 8 m8 m. If the object is making revolutions at a frequency of 3 Hz3 Hz, what is the centripetal force acting on the object?