An object with a mass of $6 k g$ $6 kg$ is revolving around a point at a distance of $8 m$ $8 m$ . If the object is making revolutions at a frequency of $4 H z$ $4 Hz$ , what is the centripetal force acting on the object?

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Answer 1 · 2017-03-28T05:48:29

The centripetal force is $= 30319.4 N$ $=30319.4N$

The centripetal force acting on an object is

$F = m r ω^{2}$ $F=mr omega^2$

The mass, $m = 6 k g$ $m=6kg$

The radius, $r = 8 m$ $r=8m$

The angularvelocity is

$ω = 4 \cdot 2 π = 8 π$ $omega=4*2pi=8pi$

So

The centripetal force is

$F = 6 \cdot 8 \cdot {(8 π)}^{2} = 30319.4 N$ $F=6*8*(8pi)^2=30319.4N$

An object with a mass of 6 kg6kg6 kg is revolving around a point at a distance of 8 m8m8 m. If the object is making revolutions at a frequency of 4 Hz4Hz4 Hz, what is the centripetal force acting on the object?