An object with a mass of $7 k g$ $7 kg$ is hanging from an axle with a radius of $36 m$ $36 m$ . If the wheel attached to the axle has a radius of $72 m$ $72 m$ , how much force must be applied to the wheel to keep the object from falling?

Question

1383 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-19T18:48:51

The force is $F = 34.3 N$ $F=34.3N$

enter image source here

The load is $L = 7 g N$ $L=7gN$

The radius of the axle is $r = 36 m$ $r=36m$

The radius of the wheel is $R = 72 m$ $R=72m$

The effort is $= F N$ $=FN$

The [cceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Taking moments about the center of the axle

$F \cdot 72 = 7 g \cdot 36$ $F*72=7g*36$

$F = \frac{7 g \cdot 36}{72} = 34.3 N$ $F=(7g*36)/72=34.3N$

The force is $F = 34.3 N$ $F=34.3N$

An object with a mass of 7 kg7kg7 kg is hanging from an axle with a radius of 36 m36m36 m. If the wheel attached to the axle has a radius of 72 m72m72 m, how much force must be applied to the wheel to keep the object from falling?