An object with a mass of $7 k g$ $7 kg$ is on a surface with a kinetic friction coefficient of $7$ $7$ . How much force is necessary to accelerate the object horizontally at $2 \frac{m}{s^{2}}$ $2 m/s^2$ ?

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An object with a mass of $7 k g$ $7 kg$ is on a surface with a kinetic friction coefficient of $7$ $7$ . How much force is necessary to accelerate the object horizontally at $2 \frac{m}{s^{2}}$ $2 m/s^2$ ?

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Answer 1 · 2016-03-14T11:01:46

$F = 494, 69 N$ $F=494,69 " "N$

Explanation:

$G = m \cdot g = 7 \cdot 9, 81 = 68, 67 N gravity of object$ $G=m*g=7*9,81=68,67 N" gravity of object"$
$N = - G normal force to the contacting surfaces$ $N=-G" normal force to the contacting surfaces"$
$F_{f} = k \cdot N = 7 \cdot 68, 67 = 480, 69 N$ $F_f=k*N=7*68,67=480,69N$
$The friction force for contacting surfaces$ $"The friction force for contacting surfaces"$
$F_{net} = m \cdot a The Newton's second law$ $F_"net"=m*a" The Newton's second law"$
$F_{net} = F - F_{f}$ $F_"net"=F-F_f$
$F - F_{f} = m \cdot a$ $F-F_f=m*a$
$F - 480, 69 = 7 \cdot 2$ $F-480,69=7*2$
$F - 480, 69 = 14$ $F-480,69=14$
$F = 480, 69 + 14$ $F=480,69+14$
$F = 494, 69 N$ $F=494,69 " "N$

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An object with a mass of $7 k g$ $7 kg$ is on a surface with a kinetic friction coefficient of $7$ $7$ . How much force is necessary to accelerate the object horizontally at $2 \frac{m}{s^{2}}$ $2 m/s^2$ ?

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An object with a mass of $7 k g$ $7 kg$ is on a surface with a kinetic friction coefficient of $7$ $7$ . How much force is necessary to accelerate the object horizontally at $2 \frac{m}{s^{2}}$ $2 m/s^2$ ?