An object with a mass of $7 k g$ $7 kg$ is on a surface with a kinetic friction coefficient of $8$ $8$ . How much force is necessary to accelerate the object horizontally at $32 \frac{m}{s^{2}}$ $32 m/s^2$ ?

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An object with a mass of $7 k g$ $7 kg$ is on a surface with a kinetic friction coefficient of $8$ $8$ . How much force is necessary to accelerate the object horizontally at $32 \frac{m}{s^{2}}$ $32 m/s^2$ ?

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Answer 1 · 2018-01-14T06:03:39

$784 N$ $784 N$

Explanation:

enter image source here As,the object is going on a horizontal surface,frictional force acting on it will be $f = u \cdot N$ $f = u*N$ or $u m g$ $umg$ i.e $(8 \cdot 7 \cdot 10$ $(8*7*10$ ) N or, 560 N

So,le't's assume we will be requiring a force of F to cause an acceleration of 32 SI units on it.

so,we can write, $F - f = m \cdot a$ $F-f = m*a$ (where, m is the mass of the object and a is its acceleration)

so, $F = (560 + 7 \cdot 32)$ $F=(560+7*32)$ N or, $784 N$ $784 N$

Answer 2 · 2018-01-14T07:33:16

The force is $= 772.8 N$ $=772.8N$

Explanation:

The mass of the object is $m = 7 k g$ $m=7kg$

The acceleration is $a = 32 m s^{- 2}$ $a=32ms^-2$

The coefficient of kinetic friction is

$μ_{k} = \frac{F_{r}}{N} = 8$ $mu_k=F_r/N=8$

The normal force is $N = 7 g N$ $N=7gN$

The frictional force is $F_{r} = μ_{k} \times N = 8 \cdot 7 g = 56 g N$ $F_r=mu_k xx N=8*7g=56gN$

The force necessary to accelerate the object is $= F N$ $=FN$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

According to Newton's Second Law

$F - F_{r} = m a$ $F-F_r=ma$

$F = m a + F_{r} = ((7 \times 32) + (56 g)) N = 772.8 N$ $F=ma+F_r=((7xx32)+(56g))N=772.8N$

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An object with a mass of $7 k g$ $7 kg$ is on a surface with a kinetic friction coefficient of $8$ $8$ . How much force is necessary to accelerate the object horizontally at $32 \frac{m}{s^{2}}$ $32 m/s^2$ ?

2 Answers

Explanation:

Explanation:

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An object with a mass of 7kg7 kg is on a surface with a kinetic friction coefficient of 8 8 . How much force is necessary to accelerate the object horizontally at 32ms2 32 m/s^2?

2 Answers

Explanation:

Explanation:

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An object with a mass of $7 k g$ $7 kg$ is on a surface with a kinetic friction coefficient of $8$ $8$ . How much force is necessary to accelerate the object horizontally at $32 \frac{m}{s^{2}}$ $32 m/s^2$ ?