An object with a mass of $7 kg$ is on a surface with a kinetic friction coefficient of $8$ . How much force is necessary to accelerate the object horizontally at $31 m/s^2$ ?

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An object with a mass of $7 kg$ is on a surface with a kinetic friction coefficient of $8$ . How much force is necessary to accelerate the object horizontally at $31 m/s^2$ ?

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Answer 1 · 2015-12-30T17:46:04

I found $765.8N$ (but check my maths!). Ciao.

Explanation:

Have a look:
enter image source here
So we get that:
$N=W=mg=7*9.8=68.6N$
From the first equation (alomg $x$ ) we get:
$F-mu_kN=ma$
$F=(8*68.6)+(7*31)=765.8N$

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An object with a mass of $7 kg$ is on a surface with a kinetic friction coefficient of $8$ . How much force is necessary to accelerate the object horizontally at $31 m/s^2$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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An object with a mass of 7 kg7 kg is on a surface with a kinetic friction coefficient of 8 8 . How much force is necessary to accelerate the object horizontally at 31 m/s^2 31 m/s^2?

1 Answer

Explanation:

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An object with a mass of $7 kg$ is on a surface with a kinetic friction coefficient of $8$ . How much force is necessary to accelerate the object horizontally at $31 m/s^2$ ?