An object with a mass of $7 k g$ $7 kg$ is on a surface with a kinetic friction coefficient of $8$ $8$ . How much force is necessary to accelerate the object horizontally at $3 \frac{m}{s^{2}}$ $3 m/s^2$ ?

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An object with a mass of $7 k g$ $7 kg$ is on a surface with a kinetic friction coefficient of $8$ $8$ . How much force is necessary to accelerate the object horizontally at $3 \frac{m}{s^{2}}$ $3 m/s^2$ ?

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Answer 1 · 2016-02-09T11:09:43

$F = 570, 36 N$ $F=570,36 " N"$

Explanation:

$F_{f} = k \cdot m \cdot g$ $F_f= k*m*g$
$F - F_{f} = m \cdot 3$ $F-F_f=m*3$
$F - k \cdot m \cdot g = m \cdot 3$ $F-k*m*g=m*3$
$F = 3 \cdot m + k \cdot m \cdot g$ $F=3*m+k*m*g$
$F = 3 \cdot 7 + 8 \cdot 7 \cdot 9, 81$ $F=3*7+8*7*9,81$
$F = 21 + 549, 36$ $F=21+549,36$
$F = 570, 36 N$ $F=570,36 " N"$

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An object with a mass of $7 k g$ $7 kg$ is on a surface with a kinetic friction coefficient of $8$ $8$ . How much force is necessary to accelerate the object horizontally at $3 \frac{m}{s^{2}}$ $3 m/s^2$ ?

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An object with a mass of 7kg7 kg is on a surface with a kinetic friction coefficient of 8 8 . How much force is necessary to accelerate the object horizontally at 3ms2 3 m/s^2?

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An object with a mass of $7 k g$ $7 kg$ is on a surface with a kinetic friction coefficient of $8$ $8$ . How much force is necessary to accelerate the object horizontally at $3 \frac{m}{s^{2}}$ $3 m/s^2$ ?