An object with a mass of 7kg is pushed along a linear path with a kinetic friction coefficient of uk(x)=4+secx. How much work would it take to move the object over #x in [(pi)/8, (pi)/3], where x is in meters?

1 Answer
Dec 1, 2017

The work is =242.2J

Explanation:

We need

secxdx=ln(tanx+secx)+C

The work done is

W=Fd

The frictional force is

Fr=μkN

The normal force is N=mg

The mass is m=7kg

Fr=μkmg

=7(4+secx)g

The work done is

W=7g13π18π(4+secx)dx

=7g[4x+ln(tanx+secx)]13π18π

=7g(43π+ln(tan(π3)+sec(π3))(12π+ln(tan(18π)+sec(18π))

=7g(3.53)

=242.2J