An object with a mass of $7 k g$ $7 kg$ is pushed along a linear path with a kinetic friction coefficient of $u_{k} (x) = 4 + sec x$ $u_k(x)= 4+secx$ . How much work would it take to move the object over #x in [(-5pi)/12, (pi)/12], where x is in meters?

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An object with a mass of $7 k g$ $7 kg$ is pushed along a linear path with a kinetic friction coefficient of $u_{k} (x) = 4 + sec x$ $u_k(x)= 4+secx$ . How much work would it take to move the object over #x in [(-5pi)/12, (pi)/12], where x is in meters?

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Answer 1 · 2018-01-02T13:14:49

The work done is $= 588.6 J$ $=588.6J$

Explanation:

$Reminder :$ $"Reminder : "$

$\int sec x d x = ln (tan x + sec x) + C$ $intsecxdx=ln(tanx+secx)+C$

The work done is

$W = F \cdot d$ $W=F*d$

The frictional force is

$F_{r} = μ_{k} \cdot N$ $F_r=mu_k*N$

The coefficient of kinetic friction is $μ_{k} = (4 + sec x)$ $mu_k=(4+secx)$

The normal force is $N = m g$ $N=mg$

The mass of the object is $m = 7 k g$ $m=7kg$

$F_{r} = μ_{k} \cdot m g$ $F_r=mu_k*mg$

$= 7 \cdot (4 + sec x) g$ $=7*(4+secx)g$

The work done is

$W = 7 g \int_{- \frac{5}{12} π}^{\frac{1}{12} π} (4 + sec x) d x$ $W=7gint_(-5/12pi)^(1/12pi)(4+secx)dx$

$= 7 g \cdot {[4 x + ln (tan x + sec x)]}_{- \frac{5}{12} π}^{\frac{1}{12} π}$ $=7g*[4x+ln(tanx+secx)]_(-5/12pi)^(1/12pi)$

$= 7 g (\frac{1}{3} π + ln (tan (\frac{π}{12}) + sec (\frac{π}{12})) - (- \frac{5}{3} π + ln (tan (- \frac{5}{12} π) + sec (- \frac{5}{12} π))$ $=7g(1/3pi+ln(tan(pi/12)+sec(pi/12))-(-5/3pi+ln(tan(-5/12pi)+sec(-5/12pi))$

$= 7 g (8.58)$ $=7g(8.58)$

$= 588.6 J$ $=588.6J$

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An object with a mass of $7 k g$ $7 kg$ is pushed along a linear path with a kinetic friction coefficient of $u_{k} (x) = 4 + sec x$ $u_k(x)= 4+secx$ . How much work would it take to move the object over #x in [(-5pi)/12, (pi)/12], where x is in meters?

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Explanation:

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Science

Math

Humanities

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An object with a mass of 7kg7 kg is pushed along a linear path with a kinetic friction coefficient of uk(x)=4+secxu_k(x)= 4+secx . How much work would it take to move the object over #x in [(-5pi)/12, (pi)/12], where x is in meters?

1 Answer

Explanation:

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An object with a mass of $7 k g$ $7 kg$ is pushed along a linear path with a kinetic friction coefficient of $u_{k} (x) = 4 + sec x$ $u_k(x)= 4+secx$ . How much work would it take to move the object over #x in [(-5pi)/12, (pi)/12], where x is in meters?