An object with a mass of 7 kg7kg is revolving around a point at a distance of 8 m8m. If the object is making revolutions at a frequency of 12 Hz12Hz, what is the centripetal force acting on the object?

1 Answer
May 30, 2016

F_C=32256 pi^2FC=32256π2

Explanation:

enter image source here

m=7 " "kgm=7 kg
r=8" "mr=8 m

f=12" "Hzf=12 Hz

v=(2pir)/T" "v/r=(2pi)/T" "(1)v=2πrT vr=2πT (1)

omega=(2pi)/T" "(2)ω=2πT (2)

"using (1) and (2)"using (1) and (2)

v/r=omega" "v=omega r" "v^2=omega^2 r^2vr=ω v=ωr v2=ω2r2

F_C=m*v^2/r" centripetal force"FC=mv2r centripetal force

F_C=(m*omega^2*r^2)/rFC=mω2r2r

F_C=m*omega^2*rFC=mω2r

F_C=m*omega^2*r" "omega=2pi f" "omega=2 pi*12" "omega^2=4pi^2*144FC=mω2r ω=2πf ω=2π12 ω2=4π2144

omega^2=576pi^2ω2=576π2

F_C=7*576pi^2*8FC=7576π28

F_C=32256 pi^2FC=32256π2