An object with a mass of $8 k g$ $8 kg$ is hanging from an axle with a radius of $12 m$ $12 m$ . If the wheel attached to the axle has a radius of $48 m$ $48 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2018-01-25T07:33:09

The force is $F = 19.6 N$ $F=19.6N$

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The load is $L = 8 g N$ $L=8gN$

The radius of the axle is $r = 12 m$ $r=12m$

The radius of the wheel is $R = 48 m$ $R=48m$

The effort is $= F N$ $=FN$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Taking moments about the center of the axle

$F \cdot 48 = 8 g \cdot 12$ $F*48=8g*12$

$F = \frac{8 g \cdot 12}{48} = N$ $F=(8g*12)/48=N$

The force is $F = 19.6 N$ $F=19.6N$

An object with a mass of 8kg8 kg is hanging from an axle with a radius of 12m12 m. If the wheel attached to the axle has a radius of 48m48 m, how much force must be applied to the wheel to keep the object from falling?