An object with a mass of $8 k g$ $8 kg$ is hanging from an axle with a radius of $25 c m$ $25 cm$ . If the wheel attached to the axle has a radius of $35 c m$ $35 cm$ , how much work would it take to turn the wheel a length equal to the circumference of the axle?

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Answer 1 · 2017-05-07T14:10:44

The work is $= 88 J$ $=88J$

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The load L=(8g)N#

Radius of axle $r = 0.25 m$ $r=0.25m$

Radius of wheel $R = 0.35 m$ $R=0.35m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 0.35 = 8 \cdot g \cdot 0.25$ $F*0.35=8*g*0.25$

$F = \frac{8 \cdot g \cdot 0.25}{0.35} = 56 N$ $F=(8*g*0.25)/0.35=56N$

The distance is

$d = 2 \cdot π \cdot 0.25 = 1.57 m$ $d=2*pi*0.25=1.57m$

The work done is

$W = F d = 56 \cdot 1.57 = 88 J$ $W=Fd=56*1.57=88J$

An object with a mass of 8kg8 kg is hanging from an axle with a radius of 25cm25 cm. If the wheel attached to the axle has a radius of 35cm35 cm, how much work would it take to turn the wheel a length equal to the circumference of the axle?