An object with a mass of $8 k g$ $8 kg$ is hanging from an axle with a radius of $27 m$ $27 m$ . If the wheel attached to the axle has a radius of $24 m$ $24 m$ , how much force must be applied to the wheel to keep the object from falling?

Question

1352 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-10T08:30:08

The force is $F = 88.2 N$ $F=88.2N$

www.odicis.org

The load is $L = 8 g N$ $L=8gN$

The radius of the axle is $r = 27 m$ $r=27m$

The radius of the wheel is $R = 24 m$ $R=24m$

The effort is $= F N$ $=FN$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Taking moments about the center of the axle

$F \cdot 24 = 8 g \cdot 27$ $F*24=8g*27$

$F = \frac{8 g \cdot 27}{24} = 88.2 N$ $F=(8g*27)/24=88.2N$

The force is $F = 88.2 N$ $F=88.2N$

An object with a mass of 8kg8 kg is hanging from an axle with a radius of 27m27 m. If the wheel attached to the axle has a radius of 24m24 m, how much force must be applied to the wheel to keep the object from falling?