An object with a mass of 8 kg8kg is hanging from an axle with a radius of 27 m27m. If the wheel attached to the axle has a radius of 18 m18m, how much force must be applied to the wheel to keep the object from falling?

1 Answer
May 2, 2018

The force is F=117.6NF=117.6N

Explanation:

www.odicis.org

The load is L=8gNL=8gN

The radius of the axle is r=27mr=27m

The radius of the wheel is R=18mR=18m

The effort is =FN=FN

The acceleration due to gravity is g=9.8ms^-2g=9.8ms2

Taking moments about the center of the axle

F*18=8g*27F18=8g27

F=(8g*27)/18=117.6NF=8g2718=117.6N

The force is F=117.6NF=117.6N