An object with a mass of $8 k g$ $8 kg$ is hanging from an axle with a radius of $27 m$ $27 m$ . If the wheel attached to the axle has a radius of $18 m$ $18 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2018-05-02T05:50:36

The force is $F = 117.6 N$ $F=117.6N$

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The load is $L = 8 g N$ $L=8gN$

The radius of the axle is $r = 27 m$ $r=27m$

The radius of the wheel is $R = 18 m$ $R=18m$

The effort is $= F N$ $=FN$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Taking moments about the center of the axle

$F \cdot 18 = 8 g \cdot 27$ $F*18=8g*27$

$F = \frac{8 g \cdot 27}{18} = 117.6 N$ $F=(8g*27)/18=117.6N$

The force is $F = 117.6 N$ $F=117.6N$

An object with a mass of 8 kg8kg8 kg is hanging from an axle with a radius of 27 m27m27 m. If the wheel attached to the axle has a radius of 18 m18m18 m, how much force must be applied to the wheel to keep the object from falling?