An object with a mass of $8 k g$ $8 kg$ is hanging from an axle with a radius of $29 m$ $29 m$ . If the wheel attached to the axle has a radius of $21 m$ $21 m$ , how much force must be applied to the wheel to keep the object from falling?

Question

1264 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-16T08:15:40

The force is $= 108.3 N$ $=108.3N$

enter image source here

The load $L = (8 g) N$ $L=(8g)N$

Radius of axle $r = 29 m$ $r=29m$

Radius of wheel $R = 21 m$ $R=21m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 21 = 8 g \cdot 29$ $F*21=8g*29$

$F = \frac{8 \cdot g \cdot 29}{21} = 108.3 N$ $F=(8*g*29)/21=108.3N$

The force is $F = 108.3 N$ $F=108.3N$

An object with a mass of 8kg8 kg is hanging from an axle with a radius of 29m29 m. If the wheel attached to the axle has a radius of 21m21 m, how much force must be applied to the wheel to keep the object from falling?