An object with a mass of $8 k g$ $8 kg$ is hanging from an axle with a radius of $30 m$ $30 m$ . If the wheel attached to the axle has a radius of $96 m$ $96 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2018-04-10T13:40:33

The force is $F = 24.5 N$ $F=24.5N$

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The load is $L = 8 g N$ $L=8gN$

The radius of the axle is $r = 30 m$ $r=30m$

The radius of the wheel is $R = 96 m$ $R=96m$

The effort is $= F N$ $=FN$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Taking moments about the center of the axle

$F \cdot 96 = 8 g \cdot 30$ $F*96=8g*30$

$F = \frac{8 g \cdot 30}{96} = 24.5 N$ $F=(8g*30)/96=24.5N$

The force is $F = 24.5 N$ $F=24.5N$

An object with a mass of 8kg8 kg is hanging from an axle with a radius of 30m30 m. If the wheel attached to the axle has a radius of 96m96 m, how much force must be applied to the wheel to keep the object from falling?