An object with a mass of $8 k g$ $8 kg$ is hanging from an axle with a radius of $30 m$ $30 m$ . If the wheel attached to the axle has a radius of $95 m$ $95 m$ , how much force must be applied to the wheel to keep the object from falling?

Question

1352 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-25T05:37:22

The force is $= 24.76 N$ $=24.76N$

enter image source here

The load L=(8g)N#

Radius of axle $r = 30 m$ $r=30m$

Radius of wheel $R = 95 m$ $R=95m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 95 = 8 \cdot g \cdot 30$ $F*95=8*g*30$

$F = \frac{8 \cdot g \cdot 30}{95} = 24.76 N$ $F=(8*g*30)/95=24.76N$

The force is $= 24.76 N$ $=24.76N$

An object with a mass of 8 kg8kg8 kg is hanging from an axle with a radius of 30 m30m30 m. If the wheel attached to the axle has a radius of 95 m95m95 m, how much force must be applied to the wheel to keep the object from falling?