An object with a mass of $8 k g$ $8 kg$ is hanging from an axle with a radius of $5 c m$ $5 cm$ . If the wheel attached to the axle has a radius of $65 c m$ $65 cm$ , how much work would it take to turn the wheel a length equal to the circumference of the axle?

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Answer 1 · 2017-07-01T05:45:57

The work is $= 1.89 J$ $=1.89J$

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The load $L = (8 g) N$ $L=(8g)N$

Radius of axle $r = 0.05 m$ $r=0.05m$

Radius of wheel $R = 0.65 m$ $R=0.65m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 0.65 = 8 \cdot g \cdot 0.05$ $F*0.65=8*g*0.05$

$F = \frac{8 \cdot g \cdot 0.05}{0.65} = 6.03 N$ $F=(8*g*0.05)/0.65=6.03N$

The force is $F = 6.03 N$ $F=6.03N$

The distance is $d = 2 π r = 0.1 π = 0.31 m$ $d=2pir=0.1pi=0.31m$

The work is

$W = F \cdot d = 6.03 \cdot 0.31 = 1.89 J$ $W=F*d=6.03*0.31=1.89J$

An object with a mass of 8 kg8kg8 kg is hanging from an axle with a radius of 5 cm5cm5 cm. If the wheel attached to the axle has a radius of 65 cm65cm65 cm, how much work would it take to turn the wheel a length equal to the circumference of the axle?