An object with a mass of $8 k g$ $8 kg$ is lying still on a surface and is compressing a horizontal spring by $\frac{5}{6} m$ $5/6 m$ . If the spring's constant is $12 \frac{k g}{s^{2}}$ $12 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

Question

An object with a mass of $8 k g$ $8 kg$ is lying still on a surface and is compressing a horizontal spring by $\frac{5}{6} m$ $5/6 m$ . If the spring's constant is $12 \frac{k g}{s^{2}}$ $12 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

1 Answer

Impact of this question

1407 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-09T16:15:11

Force F required to compress a spring by x unit is
$F = k \cdot x$ $F=k*x$ ,where k = force constant.
Here $x = \frac{5}{6} m$ $x =5/6m$
$k = 12 k g s^{- 2}$ $k=12kgs^-2$
hence Force exerted on the object of mass 1 kg is $F = 12 \frac{k g}{s^{2}} \times \frac{5}{6} m = 10 \frac{k g \cdot m}{s^{2}} = 10 N$ $F=12(kg)/s^2xx5/6m=10(kg*m)/s^2=10N$
This force is balanced by the then static frictional force as it is self adjusting one,

So the minimum value of the coefficient of static frictions
$μ_{s} = \frac{F}{N}$ $mu_s=F/N$ ,where N is the normal reaction exerted on the body by the floor. Here $N = m g = 8 \cdot 9.8 N$ $N =mg=8*9.8N$
So
$μ_{s} = \frac{F}{N} = \frac{10}{9.8 \times 8} = 0.13$ $mu_s=F/N=10/(9.8xx8)=0.13$

Science

Math

Humanities

... and beyond

An object with a mass of $8 k g$ $8 kg$ is lying still on a surface and is compressing a horizontal spring by $\frac{5}{6} m$ $5/6 m$ . If the spring's constant is $12 \frac{k g}{s^{2}}$ $12 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

An object with a mass of 8 kg8kg8 kg is lying still on a surface and is compressing a horizontal spring by 5/6 m56m5/6 m. If the spring's constant is 12 (kg)/s^212kgs212 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?

1 Answer

Related questions

Impact of this question

An object with a mass of $8 k g$ $8 kg$ is lying still on a surface and is compressing a horizontal spring by $\frac{5}{6} m$ $5/6 m$ . If the spring's constant is $12 \frac{k g}{s^{2}}$ $12 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?