An object with a mass of $8 kg$ is lying still on a surface and is compressing a horizontal spring by $5/6 m$ . If the spring's constant is $1 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2017-06-20T17:57:16

The coefficient of static friction is $=0.011$

The coefficient of static friction is

$mu_s=F_r/N$

$F_r=k*x$

The spring constant is $k=1kgs^-2$

The compression is $x=5/6m$

Therefore,

$F_r=1*5/6=0.83N$

The normal force is

$N=mg=8gN$

The coefficient of static friction is

$mu_s=(0.83)/(8g)=0.011$

An object with a mass of 8 kg8 kg is lying still on a surface and is compressing a horizontal spring by 5/6 m5/6 m. If the spring's constant is 1 (kg)/s^21 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?