An object with a mass of 8kg is on a ramp at an incline of π8. If the object is being pushed up the ramp with a force of 9N, what is the minimum coefficient of static friction needed for the object to remain put?

1 Answer
Jul 21, 2017

μs0.290

Explanation:

We're asked to find the minimum value of the coefficient of static friction μs between the incline and object so that the object remains stationary.

![d2gne97vdumgn3.cloudfront.net](useruploads.socratic.org)

Since its mass is given as 8 kg,

mgsinθ=(8lkg)(9.81lm/s2)sin(π8)=30.0 N

The normal force magnitude n is

n=mgcosθ=(8lkg)(9.81lm/s2)cos(π8)=72.5 N

Since the object is supposed to be stationary, the body is in equilibrium (sum of all forces acting on body equals zero), so (taking positive x direction as up the incline)

Fx=Fapplied+fsmgsinθ=0

So

fs=mgsinθFapplied

The applied force is given as 9 N, so we have

fs=30.0 N 9 N = 21.0 N

Now that we know the static friction force fs, we can figure out the coefficient of static friction using the equation

fsμsn

μsfsn=21.0lN72.5lN=0.290