An object with a mass of 8 kg is traveling in a circular path of a radius of 12 m. If the object's angular velocity changes from 9 Hz to 12 Hz in 6 s, what torque was applied to the object?

1 Answer
Apr 13, 2017

The torque was =3619.1Nm

Explanation:

The torque is the rate of change of angular momentum

tau=(dL)/dt=(d(Iomega))/dt=I(domega)/dt

For the object, the moment of inertia is

I=(mr^2)

So, I=8*(12)^2=1152kgm^2

The rate of change of angular velocity is

(domega)/dt=(12-9)/6*2pi

=(pi) rads^(-2)

So the torque is tau=1152*(pi) =3619.1Nm