Question

An object with a mass of `9 kg` is acted on by two forces. The first is `F_1= < -3 N , 8 N>` and the second is `F_2 = < 6 N, -3 N>`. What is the objects rate and direction of acceleration?

Answer 1

Acceleration `a=sqrt34/9=0.6478835439" "m/sec^2`
directed `theta=59^@2' 10.48''`

Explanation:

Adding the forces `F_1` and `F_2`

`F=sqrt((6-3)^2+(8-3)^2)`

`F=sqrt(9+25)`

`F=sqrt(34)`

Acceleration `a=(sum F)/m=sqrt34/9=0.6478835439" "m/sec ^2`

Direction `theta=tan^-1 (8-3)/(6-3)=59^@2' 10.48''`

God bless....I hope the explanation is useful.