An object with a mass of 99 kgkg is on a plane with an incline of - pi/4 π4. If it takes 1515 NN to start pushing the object down the plane and 77 NN to keep pushing it, what are the coefficients of static and kinetic friction?

1 Answer
Apr 25, 2016

The coefficient of static friction is mu_s=1.24μs=1.24 and the coefficient of kinetic friction is mu_k=1.11μk=1.11.

Explanation:

The negative sign on the angle is not relevant in this case: the angle of the inclined plane is pi/4π4 radiansradians (45^o45o). The negative sign just shows that the slope increases right-to-left rather than left-to-right.

The force perpendicular to the plane, the normal force, will be given by:

F_N=mgsinTheta=9*9.8*sin(pi/4)=62.4 N

Based on this, the frictional force will be:

F_"frict"=muF_N

Rearranging,

mu=(F_"frict")/(F_N)

We will find two different values, the static friction, mu_s, and the kinetic friction, mu_k.

The force parallel to the plane due to gravity will be given by:

F=mgcosTheta=9*9.8*cos(pi/4)=62.4 N

Overcoming the force of static friction requires this parallel force plus 15 N, a total frictional force of 77.4 N.

mu_s=(F_"frict")/(F_N)=77.4/62.4=1.24

Once it is moving, keeping it moving only requires 7 N in addition to the parallel force, a total of 69.4 N.

mu_k=(F_"frict")/(F_N)=69.4/62.4=1.11

Coefficients of friction do not have units.