Area of Pentagons?

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Area of Pentagons?

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Answer 1 · 2017-05-10T03:15:32

width $= 4 x = 4 \times 10 = 40 c m$ $=4x=4xx10=40cm$

Explanation:

As the two pentagons are similar, their corresponding sides are in the same ratio.

$\Rightarrow \frac{4 x}{48} = \frac{x}{x + 2}$ $=> (4x)/48=x/(x+2)$
$\Rightarrow 4 x (x + 2) = 48 x$ $=> 4x(x+2)=48x$
$\Rightarrow 4 x^{2} + 8 x = 48 x$ $=> 4x^2+8x=48x$
$\Rightarrow 4 x^{2} - 40 x = 0$ $=> 4x^2-40x=0$
$\Rightarrow 4 x (x - 10) = 0$ $=> 4x(x-10)=0$
$\Rightarrow x = 0, or 10$ $=> x=0, or 10$
As $x \neq 0$ $x!=0$ ,
$\Rightarrow x = 10$ $=> x=10$

Hence, width of the badge = $4 x = 4 \times 10 = 40$ $4x=4xx10=40$ cm

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Area of Pentagons?

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