Assume y varies inversely as x, how do you write the equation given y=-6 when x=-3?

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Assume y varies inversely as x, how do you write the equation given y=-6 when x=-3?

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Answer 1 · 2017-05-29T15:49:40

$y \propto (\frac{1}{x})$ $yprop(1/x)$

so, $y = \frac{k}{x}$ $y = k/x$

With x = -3 and y = -6 we have:

$- 6 = \frac{k}{- 3}$ $-6 = k/-3$

=> k = 18

Then, $y = \frac{18}{x}$ $y = 18/x$

or, $x y = 18$ $xy = 18$

:)>

Answer 2 · 2017-05-29T15:58:25

$y = \frac{18}{x}$ $y = 18/x$

Explanation:

This sounds like inverse proportionality.

The standard writing for such a formula is: $y = \frac{k}{x}$ $y = k/x$

Given the information, y = -6 when x =-3, we can find the constant "k".
$- 6 = \frac{k}{- 3} \Leftrightarrow k = - 6 \cdot (- 3) = 18$ $-6 = k/-3 iff k = -6*(-3)=18$

Now we know "k", we write the formula that sitifies y = -6 when x = -3 as $y = \frac{18}{x}$ $y = 18/x$

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Assume y varies inversely as x, how do you write the equation given y=-6 when x=-3?

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