At 22.5 ºC and 1.25 atm pressure, a sample of carbon dioxide gas occupies a volume of 2.65 L. How many moles of the gas are present?

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At 22.5 ºC and 1.25 atm pressure, a sample of carbon dioxide gas occupies a volume of 2.65 L. How many moles of the gas are present?

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Answer 1 · 2017-11-13T03:07:54

$1.36 \times 10^{- 1}$ $1.36 xx 10^(-1)$ ${mol CO}_{2}$ $"mol CO"_2$

Explanation:

$P V = n R T$ $PV=nRT$

We want to find the no. of moles, which is $n$ $n$ , so

$n = \frac{P V}{R T}$ $n= (PV)/(RT)$

Here

$P = 1.25 atm$ $"P = 1.25 atm"$

$V = 2.65 L$ $V = "2.65 L"$

$R = 0.0821 atm(L)/mol(K)$ $R= "0.0821 atm(L)/mol(K)"$

$T = {22.5}^{\circ} C + 273.15 = 295.7 K$ $T = 22.5^@"C" +273.15 = "295.7 K"$

Now plug it into the formula

$n = \frac{(1.25 atm) (2.65 L)}{(0.0821 atm(L)/mol(K)) (295.7 K)}$ $n = (("1.25 atm")("2.65 L"))/(("0.0821 atm(L)/mol(K)")("295.7 K"))$

$n = \frac{3.3125}{24.273}$ $n = 3.3125/24.273$ $mol$ $"mol"$

$n = 1.36 \times 10^{- 1}$ $n = 1.36 xx 10^(-1)$ ${mol CO}_{2}$ $"mol CO"_2$

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At 22.5 ºC and 1.25 atm pressure, a sample of carbon dioxide gas occupies a volume of 2.65 L. How many moles of the gas are present?

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