At equilibrium, the partial pressure of $S O_{2}$ $SO_2$ is 35.0 atm and that of $O_{2}$ $O_2$ is 15.9 atm. What is the partial pressure of $S O_{3}$ $SO_3$ in atm?

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Answer 1 · 2017-03-06T08:32:32

You need to specify the equilibrium constant.......

$2 S O_{2} + O_{2} \to 2 S O_{3}$ $2SO_2+O_2rarr2SO_3$

$K_{p} = \frac{p_{S O_{3}}^{2}}{p_{S O_{2}}^{2} \times p_{O_{2}}}$ $K_p=(p_(SO_3)^2)/(p_(SO_2)^2xxp_(O_2))$ $=$ $=$ $? ?$ $??$

We need to know $K_{p}$ $K_p$ in order to access $p_{S O_{3}}$ $p_(SO_3)$ .

At equilibrium, the partial pressure of SO2SO_2 is 35.0 atm and that of O2O_2 is 15.9 atm. What is the partial pressure of SO3SO_3 in atm?