Question

At room temperature, an oxygen molecule, with mass of `5.31 x 10^-26 kg`, typically has a KE of about `6.21 x 10-21` J. How fast is the molecule moving?

Answer 1

`484ms^(-1)`

Explanation:

`E_k=(mv^2)/2=6.21*10^(-21)J`

`6.21*10^(-21)=(5.31*10^(-26)v^2)/2`

`v=sqrt((2(6.21*10^(-21)))/(5.31*10^(-26)))=483.630339~~484ms^(-1)`