Question

At what temperature will 14.0 g of `H_2` occupy a volume of 15.5L at a pressure of 204 kPa?

Answer 1

`T=(PV)/(nR)~=50*K`

Explanation:

Of course, we need to find the appropriate gas constant.

This site gives me `R= 8.314*L*kPa* K^-1* mol^-1`.

Given this, we plug in the numbers:

`T=(204*kPaxx15.5*L)/((14.0*g)/(2.016*g*mol^-1)xx8.314*L*kPa* K^-1* mol^-1)`

We should get an answer in `1/K^-1=1/(1/K)=K` as required for an `"absolute temperature"`.

The temperature is so low because there is a large molar quantity of dihydrogen. At this temperature we would anticipate some deviation from ideality. We are in no position to assess this.