Bombarding Br-81 with gamma rays gives a radioactive nuclide and a neutron. What is the radionuclide?

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Bombarding Br-81 with gamma rays gives a radioactive nuclide and a neutron. What is the radionuclide?

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Answer 1 · 2016-03-30T09:48:27

$_{35}^{80} Br$ $"_35^80text(Br)$

Explanation:

$_{35}^{81} Br$ $"_35^81text(Br)$ is an isotope of Bromine known to stable. It is bombarded with $γ$ $gamma$ rays to give two products a radioactive nuclide and a neutron. The equation can be written as

$_{35}^{81} Br + γ$ $"_35^81text(Br)+gamma$ $\to$ $->$ $X +_{0}^{1} n$ $text(X)+"_0^1text(n)$

Comparing the charges and atomic masses on the both sides of the nuclear reaction, we observe that the daughter nuclide has

the same atomic number, and
its mass number is 1 less than the parent.

It is therefore, clear that the radioactive nuclide is an isotope of Bromine with mass number one less than the parent.
Therefore, the daughter is $_{35}^{80} Br$ $"_35^80text(Br)$

It is known that $_{35}^{80} Br$ $"_35^80text(Br)$ is radioactive and decays via $β$ $beta$ decay as below.

$_{35}^{80} Br \to β^{-}$ $"_35^80text(Br)-> beta^-$ $+_{36}^{80} Kr$ $+ "_36^80text(Kr)$
$_{35}^{80} Br \to β^{+}$ $"_35^80text(Br)-> beta^+$ $+_{34}^{80} Se$ $+"_34^80text(Se)$

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Bombarding Br-81 with gamma rays gives a radioactive nuclide and a neutron. What is the radionuclide?

1 Answer

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