Bong walks 100 m due North and then 150 m in a direction N 37 deg. E. How far is Bong from his original position?

1 Answer
Apr 19, 2018

color(purple)("Bong is " 181.38 m " away from the original position"

Explanation:

![http://www.dummies.com/education/math/trigonometry/laws-of-sines-and-cosines/](useruploads.socratic.orguseruploads.socratic.org)

Applying Law of Cosines,

c^2 = a^2 + b^2 - 2 * a * b * cos C

" Given : " b = 100 m, a= 150 m, hat C = 180-37 = 143^@

c = sqrt((100^2 + 150^2 - (2 * 100 * 150 * cos 143))

c = sqrt(10000 + 22500 - 500 cos 143)

color(purple)(c = 181.38 m