By using the intercept method, how to find the equations of the straight lines passing through (-3,0) and (0,2)?

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Answer 1 · 2018-01-22T06:08:24

$y=2/3x+2$

Given -

$(-3,0);(0,2)$

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When the two intercepts are given, we can form the equation as

$x/a+y/b=1$

Where -

$a$ - x- intercept
$b$ - y-intercept

$a=-3$
$b=2$

Plugin these values in the formula

$x/(-3)+y/2=1$
Multiply both side with $6$
$-2x+3y=6$

$3y=2x+6$
$y=2/3x+2$