By using the intercept method, how to find the equations of the straight lines passing through (-3,0) and (0,2)?

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By using the intercept method, how to find the equations of the straight lines passing through (-3,0) and (0,2)?

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Answer 1 · 2018-01-22T06:08:24

$y = \frac{2}{3} x + 2$ $y=2/3x+2$

Explanation:

Given -

$(- 3, 0); (0, 2)$ $(-3,0);(0,2)$

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When the two intercepts are given, we can form the equation as

$\frac{x}{a} + \frac{y}{b} = 1$ $x/a+y/b=1$

Where -

$a$ $a$ - x- intercept
$b$ $b$ - y-intercept

$a = - 3$ $a=-3$
$b = 2$ $b=2$

Plugin these values in the formula

$\frac{x}{- 3} + \frac{y}{2} = 1$ $x/(-3)+y/2=1$
Multiply both side with $6$ $6$
$- 2 x + 3 y = 6$ $-2x+3y=6$

$3 y = 2 x + 6$ $3y=2x+6$
$y = \frac{2}{3} x + 2$ $y=2/3x+2$

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By using the intercept method, how to find the equations of the straight lines passing through (-3,0) and (0,2)?

1 Answer

Explanation:

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