Calcium carbonate, $C a C O_{3}$ $CaCO_3$ has a Ksp value of $1.4 x 10^{- 8}$ $1.4 x 10^-8$ , what is the solubility of $C a C O_{3}$ $CaCO_3$ ?

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Calcium carbonate, $C a C O_{3}$ $CaCO_3$ has a Ksp value of $1.4 x 10^{- 8}$ $1.4 x 10^-8$ , what is the solubility of $C a C O_{3}$ $CaCO_3$ ?

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Answer 1 · 2016-08-24T08:05:18

$C a C O_{3} (s) ⇌ C a^{2 +} + C O_{3}^{2 -}$ $CaCO_3(s) rightleftharpoons Ca^(2+) + CO_3^(2-)$

Explanation:

$K_{s p} = [C a^{2 +}] [C O_{3}^{2 -}]$ $K_(sp)=[Ca^(2+)][CO_3^(2-)]$ $=$ $=$ $1.4 \times 10^{- 8}$ $1.4xx10^-8$ .

If we call the solubility $S$ $S$ , then $S = [C a^{2 +}] = [C O_{3}^{2 -}]$ $S=[Ca^(2+)]=[CO_3^(2-)]$ , and,

$K_{s p} = [C a^{2 +}] [C O_{3}^{2 -}]$ $K_(sp)=[Ca^(2+)][CO_3^(2-)]$ $=$ $=$ $1.4 \times 10^{- 8}$ $1.4xx10^-8$ $=$ $=$ $S^{2}$ $S^2$

So $C a^{2 +}$ $Ca^(2+)$ $=$ $=$ $\sqrt{K_{sp}}$ $sqrt{K_"sp"}$ $=$ $=$ $\sqrt{1.4 \times 10^{- 8}}$ $sqrt(1.4xx10^-8)$ $=$ $=$ $1.18 \times 10^{- 4}$ $1.18xx10^(-4)$ $m o l \cdot L^{- 1}$ $mol*L^-1$ .

$Solubility$ $"Solubility"$ $=$ $=$ $1.18 \times 10^{- 4} \times 100.09 \cdot g \cdot m o l^{- 1}$ $1.18xx10^-4xx100.09*g*mol^-1$ $=$ $=$ $? ? g \cdot L^{- 1}$ $??g*L^-1$

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Calcium carbonate, $C a C O_{3}$ $CaCO_3$ has a Ksp value of $1.4 x 10^{- 8}$ $1.4 x 10^-8$ , what is the solubility of $C a C O_{3}$ $CaCO_3$ ?

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Explanation:

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Calcium carbonate, $C a C O_{3}$ $CaCO_3$ has a Ksp value of $1.4 x 10^{- 8}$ $1.4 x 10^-8$ , what is the solubility of $C a C O_{3}$ $CaCO_3$ ?