Calculate the level in decibels for a sound having an intensity of 5.00x10^-4Wm^-2?

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Answer 1 · 2018-06-26T16:09:36

#76.99\ db#

Intensity level of sound of power #I# in #db# as follows

#|text{intensity level of sound}=10\log_{10}(\frac{I}{I_o})\ db#

Hence, intensity level of sound of power #I=5\times10^{-5}\ W/m^2# in #db# as follows

#|text{intensity level of sound}=10\log_{10}(\frac{5\times10^{-5}}{10^{-12}})\ db#

#=10\log_{10}(5\times10^{7})\ db#

#=10(\log_{10}(5)+7)\ db#

#=10(0.699+7)\ db#

#=76.99\ db#