Calculate the mass of $K C l$ $KCl$ that should be dissolved to form a 5 ppm $C l^{-}$ $Cl^-$ ion solution having a total volume of 20 $d m^{3}$ $dm^3$ ?

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Answer 1 · 2015-07-17T18:05:00

The mass of KCl is 0.2 g.

$5 ppm$ $"5 ppm"$ means $5 g of solute$ $"5 g of solute"$ in $10^{6} g of solution$ $10^6 "g of solution"$ .

$"Mass of soln" = 20 cancel("dm³ soln") × "1000 g soln"/(1 cancel("dm³ soln")) = "20 000 g soln"$

$"Mass of Cl"^(-) = 20 000 cancel("g soln") × ("5 g Cl"^-)/(10^6 cancel("g soln")) = "0.10 g Cl"^-$

$"Mass of KCl" = 0.10 cancel("g Cl⁻")× "74.55 g KCl"/(35.45cancel("g Cl⁻")) = "0.2 g KCl"$

Calculate the mass of KClKClKCl that should be dissolved to form a 5 ppm Cl^-Cl−Cl^- ion solution having a total volume of 20 dm^3dm3dm^3?