Calculate the percentage yield of ferrous sulfide if 3 moles of iron produces 220 grams of ferrous sulfide?

1 Answer
May 18, 2017

First we calculate the theoretic yield.

Explanation:

3 mol of Fe should yield 3 mol FeS

m(FeS)=m(Fe)+m(S)=55.85+32.07=87.92

3 mol should have a mass of 3xx87.92=263.76

So percent yield is 220/263.76=0.834~~83%