Can anyone demonstrate the workings to obtain the solution? Trigonometry Trigonometric Identities and Equations Double Angle Identities 1 Answer Shwetank Mauria Jan 20, 2017 (E) ((14-7x)/(x^2-x))/((x-2)/(x-1))=-7/x14−7xx2−xx−2x−1=−7x Explanation: ((14-7x)/(x^2-x))/((x-2)/(x-1))14−7xx2−xx−2x−1 = ((7(2-x))/(x(x-1)))/((x-2)/(x-1))7(2−x)x(x−1)x−2x−1 = (-7(x-2))/(x(x-1))xx(x-1)/(x-2)−7(x−2)x(x−1)×x−1x−2 = (-7cancel((x-2)))/(xcancel((x-1)))xxcancel(x-1)/cancel(x-2) = -7/x Answer link Related questions What are Double Angle Identities? How do you use a double angle identity to find the exact value of each expression? How do you use a double-angle identity to find the exact value of sin 120°? How do you use double angle identities to solve equations? How do you find all solutions for sin 2x = cos x for the interval [0,2pi]? How do you find all solutions for 4sinthetacostheta=sqrt(3) for the interval [0,2pi]? How do you simplify cosx(2sinx + cosx)-sin^2x? If tan x = 0.3, then how do you find tan 2x? If sin x= 5/3, what is the sin 2x equal to? How do you prove cos2A = 2cos^2 A - 1? See all questions in Double Angle Identities Impact of this question 1479 views around the world You can reuse this answer Creative Commons License