Can anyone demonstrate the workings to obtain the solution? Trigonometry Trigonometric Identities and Equations Double Angle Identities 1 Answer Shwetank Mauria Jan 20, 2017 (E) #((14-7x)/(x^2-x))/((x-2)/(x-1))=-7/x# Explanation: #((14-7x)/(x^2-x))/((x-2)/(x-1))# = #((7(2-x))/(x(x-1)))/((x-2)/(x-1))# = #(-7(x-2))/(x(x-1))xx(x-1)/(x-2)# = #(-7cancel((x-2)))/(xcancel((x-1)))xxcancel(x-1)/cancel(x-2)# = #-7/x# Answer link Related questions What are Double Angle Identities? How do you use a double angle identity to find the exact value of each expression? How do you use a double-angle identity to find the exact value of sin 120°? How do you use double angle identities to solve equations? How do you find all solutions for #sin 2x = cos x# for the interval #[0,2pi]#? How do you find all solutions for #4sinthetacostheta=sqrt(3)# for the interval #[0,2pi]#? How do you simplify #cosx(2sinx + cosx)-sin^2x#? If #tan x = 0.3#, then how do you find tan 2x? If #sin x= 5/3#, what is the sin 2x equal to? How do you prove #cos2A = 2cos^2 A - 1#? See all questions in Double Angle Identities Impact of this question 1399 views around the world You can reuse this answer Creative Commons License