Can someone give me a clue, how can i solve this? I want something like: #x=pi/4+kpi# ---> Solve this: #2sin^2(x)-sin^2(2x)=cos^2(2x)#
#2sin^2(x)-sin^2(2x)=cos^2(2x)#
It should be:
#x=pi/4+kpi# AND #x=(3pi)/4+kpi#
It should be:
2 Answers
Apr 6, 2017
See below.
Explanation:
You can write also
so
so
Apr 6, 2017
Given:
Add
Substitute 1 for