Can you find the limit? #Lim_(xrarroo)xe^(-x/2)#

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#Lim_(xrarroo)xe^(-x/2)#

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Answer 1 · 2017-12-07T21:40:51

#Lim_(xrarroo)xe^(-x/2)=0#

#Lim_(xrarroo)xe^(-x/2)=Lim_(xrarroo)x/e^(x/2)=oo/oo=Lim_(xrarroo)1/((e^(x/2))*1/2)=Lim_(xrarroo)2/e^(x/2)=2/e^oo=0#