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Can you help with this?

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Answer 1 · 2017-12-04T07:03:42

$80.41, 279.59$ $80.41, 279.59$ Degrees

Explanation:

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${sec}^{2} x - 6 sec x = 0$ $sec^2x-6secx=0$

$sec x (sec x - 6) = 0$ $secx(secx-6)=0$

$sec x = 0$ $secx=0$ , or $\frac{1}{cos x} = 0$ $1/cosx=0$ . This answer is not valid because it it means that $cos x = \infty$ $cosx=oo$ . $cos$ $cos$ values can only be between $\pm 1$ $+-1$ .

$sec x - 6 = 0$ $secx-6=0$
$sec x = 6$ $secx=6$ , or $\frac{1}{cos x} = 6$ $1/cosx=6$

$cos x = \frac{1}{6}$ $cosx=1/6$

$x = arccos (\frac{1}{6}) = 80.41$ $x=arccos(1/6)=80.41$ Degrees

$x = 360 - 80.41 = 279.59$ $x=360-80.41=279.59$ Degrees

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