Question

Cavin shoots an arrow at 30.0° above the horizontal. Its velocity is 49 m/s, and it hits the target. What is the maximum height the arrow will attain?

Answer 1

`30.62"m"`

Explanation:

`v^2=u^2+2as`

`:.0=(49sin30)^2-2xx9.8xxh`

`:.h=600.25/19.6=30.62"m"`