Circle A has a radius of 2 2 and a center at (5 ,2 )(5,2). Circle B has a radius of 5 5 and a center at (3 ,4 )(3,4). If circle B is translated by <2 ,1 ><2,1>, does it overlap circle A? If not, what is the minimum distance between points on both circles?
1 Answer
Explanation:
What we have to do here is
color(blue)"compare"compare the distance ( d ) between the centres of the circles to thecolor(blue)"sum of radii"sum of radii
• "if sum of radii ">d" then circles overlap"∙if sum of radii >d then circles overlap
• "if sum of radii "< d" then no overlap of circles"∙if sum of radii <d then no overlap of circles Before finding d we require to find the coordinates of the 'new' centre of B under the given translation which does not change the shape of the circle only it's position.
" Under a trans;ation " ((2),(1))
(3,4)to(3+2,4+1)to(5,5)larrcolor(red)" new centre of B" Since the x-ccordinates of both centres are 5 then the centres lie on the same vertical line and d is the difference in their y-coordinates.
rArrd=5-2=3
"sum of radii = radius of A + radius of B "=2+5=7
"since sum of radii"> d" then circles overlap"
graph{(y^2-4y+x^2-10x+25)(y^2-10y+x^2-10x+25)=0 [-13.8, 13.91, -6.93, 6.92]}