Circle A has a radius of 2 2 and a center of (2 ,7 )(2,7). Circle B has a radius of 6 6 and a center of (7 ,5 )(7,5). If circle B is translated by <-1 ,1 ><1,1>, does it overlap circle A? If not, what is the minimum distance between points on both circles?

1 Answer

circle B do not overlap.
Shortest distance is 3.764-2=1.7643.7642=1.764

Explanation:

Circle A
Center (2,7)(2,7)
radius 22

Equation of circle A
(x-2)^2+(y-7)^2=2^2(x2)2+(y7)2=22

Circle B
Center (7,5)(7,5)
radius 66

Equation of circle B
(x-7)^2+(y-5)^2=6^2(x7)2+(y5)2=62

ranslation of B
<-1,1>
Center of B after translation ((7-1),(5+1))
Center of B after translation (6,6)

Equation of circle B after translation
(x-6)^2+(y-6)^2=6^2

Intersection of the circles
(x-2)^2+(y-7)^2=2^2
and
(x-6)^2+(y-6)^2=6^2
can be found out

Distance from center of Circle A to
center of Circle B is
(2,7) ---- (6,6)
=sqrt((6-7)^2+(6-2)^2
=sqrt((1+4)
=sqrt(5)
=2.236

Radius of circle A is 2
point on the Perimeter of the circle B is away from its center by 6
point on the Perimeter of the circle B is away from (2,7) is6-2.236
=3.764
Hence, the two circles donot overlap.
Shortest distance is 3.764-2=1.764