Circle A has a radius of 3 and a center at (1 ,2 ). Circle B has a radius of 5 and a center at (3 ,4 ). If circle B is translated by <2 ,1 >, does it overlap circle A? If not, what is the minimum distance between points on both circles?
1 Answer
Explanation:
What we have to do here is
color(blue)"compare " the distance (d) between the centres to thecolor(blue)"sum of radii"
• " if "a>d" then circles overlap"
• " if "a < d" then no overlap"
"before we can calculate d we require to find the new "
"centre of B under the given translation"
"under the translation "<2,1>
(3,4)to(3+2,4+1)to(5,5)larrcolor(red)"new centre of B"
"to calculate d use the "color(blue)"distance formula"
color(red)(bar(ul(|color(white)(2/2)color(black)(d=sqrt((x_2-x_1)^2+(y_2-y_1)^2))color(white)(2/2)|)))
"let "(x_1,y_1)=(1,2)" and "(x_2,y_2)=(5,5)
d=sqrt((5-1)^2+(5-2)^2)=sqrt(16+9)=5
"sum of radii "=3+5=8
"since sum of radii ">d" then circles overlap"
graph{((x-1)^2+(y-2)^2-9)((x-5)^2+(y-5)^2-25)=0 [-20, 20, -10, 10]}