Circle A has a radius of 5 5 and a center of (3 ,2 )(3,2). Circle B has a radius of 3 3 and a center of (1 ,4 )(1,4). If circle B is translated by <2 ,-1 ><2,−1>, does it overlap circle A? If not, what is the minimum distance between points on both circles?
1 Answer
circle B inside circle A
Explanation:
What we have to do here is
color(blue)"compare"compare the distance ( d) between the centres of the circles to thecolor(blue)"sum/difference of the radii"sum/difference of the radii • If sum of radii > d , then circles overlap
• If sum of radii < d , then no overlap
• If difference of radii > d , then one circle inside the other
Before calculating d we must find the ' new' centre of B under the given translation which does not change the shape of the circle only it's position.
Under a translation
((2),(-1))
(1,4)to(1+2,4-1)to(3,3)larr" new centre of B" Since the centres (3 ,2) and (3 ,3) have the same x-coordinate they lie on the vertical line with equation x = 3 and d is the difference of the y-coordinates.
rArrd=3-2=1 difference of radii= radius of A - radius of B = 5 - 3 = 2
Since difference of radii > d , then circle B is inside circle A.
graph{(y^2-4y+x^2-6x-12)(y^2-6y+x^2-6x+9)=0 [-20, 20, -10, 10]}