Complete the half equation?: $M n O_{4}^{-} + X \to M n^{2} + Y$ $MnO_4^-" + X -> Mn^2+Y$ What are X and Y?

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Complete the half equation?: $M n O_{4}^{-} + X \to M n^{2} + Y$ $MnO_4^-" + X -> Mn^2+Y$ What are X and Y?

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Answer 1 · 2018-04-13T17:17:13

$X = 8 H^{+}$ $X=8H^+$
$Y = 4 H_{2} O$ $Y=4H_2O$

Explanation:

$X = 8 H^{+}$ $X=8H^+$
$Y = 4 H_{2} O$ $Y=4H_2O$
so. the required eqn is,
$M n O_{4}^{-} + 8 H^{+} \to M n^{2 +} + 4 H_{2} O$ $MnO_4^(-) +8H^+ rarr Mn^(2+)+4H_2O$
to balance the $e^{-}$ $e^-$ ,
$M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O$ $MnO_4^(-) +8H^(+)+5e^(-) rarr Mn^(2+)+4H_2O$

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Complete the half equation?: $M n O_{4}^{-} + X \to M n^{2} + Y$ $MnO_4^-" + X -> Mn^2+Y$ What are X and Y?

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Complete the half equation?: MnO−4+X→Mn2+YMnO_4^-" + X -> Mn^2+Y What are X and Y?

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Complete the half equation?: $M n O_{4}^{-} + X \to M n^{2} + Y$ $MnO_4^-" + X -> Mn^2+Y$ What are X and Y?